Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        The equation 2x2 + 2(p + 1)x + p = 0, where p is real, always has roots that are
*  Equal
*  Equal in magnitude but opposite in sign
*  Irrational
*  Real
*  Complex Conjugates```
8 years ago

vijay narang
27 Points
```										The value of the discriminant of a quadratic equation will determine the nature of the roots of a quadratic equation.
The discriminant of a quadratic equation ax2 + bx + c = 0 is given by b2 - 4ac.

* If the value of the discriminant is positive, i.e. greater than '0', then the roots of the quadratic equation will be real.
* If the value of the discriminant is '0', then the roots of the quadratic equation will be real and equal.
* If the value of the discriminant is negative, i.e. lesser than '0', then the roots of the quadratic equation will be imaginary. The two roots will be complex conjugates of the form p + iq and p - iq.

Using this basic information, we can solve this problem as shown below.

In this question, a = 2, b = 2(p + 1) and c = p

Therefore, the disciminant will be (2(p + 1))2 - 4*2*p = 4(p + 1)2 - 8p
= 4[(p + 1)2 - 2p]
= 4[(p2 + 2p + 1) - 2p]
= 4(p2 + 1)

For any real value of p, 4(p2 + 1) will always be positive as p2 cannot be negative for real p.

Hence, the discriminant b2 - 4ac will always be positive.

When the discriminant is greater than '0' or is positive, the roots of a quadratic equation will be real.
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details