MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
VISHWESH RAVI Grade: 12th Pass
        























In the expansion of , the term which does not contain x is :
10C0
10C7
10C4
none
7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Vishwesh


simplyfy the given expression


it will become


 {(x1/3 +1) -(x-1 + x-1/2)}10


={x1/3 +1 -x-1 - x-1/2}10


use multinominal theorem and find general term of series


=10!/p!q!r!s! [(x1/3)p(1)q( -x-1 )r(- x-1/2 )s]


=10!/p!q!r!s! [(xp/3 -r-s/2](-1)r+s   where p+q+r+s =10


for the term does not contain x


   p/3 -r-s/2 =0


now find out all possible value


put p=r=s=0


so q=10


so general term become


10C10  or 10C0


Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 1,272 off
USE CODE: Neerajwin
Get extra Rs. 187 off
USE CODE: Neerajwin

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details