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VISHWESH RAVI Grade: 12th Pass
        

























The positive value of a so that the co-efficient of x5 is equal to that of x15 in the expansion of is
1
2








6 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Vishwesh


general term in the series = 10Cr(x2)10-r(a/x3)r


                                                        = 10Crx20-5r(a)r


for x15   20-5r =15


              r=1


  so coefficient of this term = 10C1a


for x5    20-5r =5


             r=3


so coefficient of this term = 10C3a3


 


now equate


   10C1= 10C3a3


    a = 1/23


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Badiuddin



6 years ago
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