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Dear Vishwesh
general term in the series = 10Cr(x2)10-r(a/x3)r
= 10Crx20-5r(a)r
for x15 20-5r =15
r=1
so coefficient of this term = 10C1a
for x5 20-5r =5
r=3
so coefficient of this term = 10C3a3
now equate
10C1a = 10C3a3
a = 1/2√3
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