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VISHWESH RAVI Grade: 12th Pass
```

The positive value of a so that the co-efficient of x5 is equal to that of x15 in the expansion of  is

1.

2.

3.
1

4.
2

```
7 years ago

## Answers : (1)

147 Points
```										Dear Vishwesh
general term in the series = 10Cr(x2)10-r(a/x3)r
= 10Crx20-5r(a)r
for x15   20-5r =15
r=1
so coefficient of this term = 10C1a
for x5    20-5r =5
r=3
so coefficient of this term = 10C3a3

now equate
10C1a  = 10C3a3
a = 1/2√3
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```
7 years ago
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