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VISHWESH RAVI Grade: 12th Pass
        























The sum of the binomial coefficients of is equal to 256 . The constant term in the expansion is
1120
2110
1210
none
7 years ago

Answers : (1)

Nehal Wani
21 Points
										

[2x+1/x]n


Sum of binomial coefficients:


nC0+ nC1+ nC2+ nC3+………………….+ nCn+ nCn=2n


256=2n


Therefore n=8


Tr=nCr(2x)n-r(x)-r= nCr2n-rxn-2r= 8Cr28-rx8-2r


8-2r=0


⇒  r=4


8Cr28-rx8=8C424=1120

7 years ago
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