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```        SHOW THAT THE RATIO OF SUM OF FIRST n terms of gp  to sum of terms from [n+1]th to [2n]th term  is 1/r raise to power n
```
7 years ago

SHAIK AASIF AHAMED
74 Points
```										Hello student,Please find the answer to your question belowGiven The numbers are in GPThen sum of first n terms of a GP is a(rn-1)/r-1Sum of terms from n+1 to 2n terms of a GP is a(r2n-1)/r-1So The ratio of them gives (rn-1)/(r2n-1)=(1/rn+1)But the 1 in denominator can be neglected because rnis>>>1SoTHE RATIO OF SUM OF FIRST n terms of gp to sum of terms from [n+1]th to [2n]th term is (1/rn)
```
3 years ago
kasilaxmi
37 Points
```										hi farru
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3 years ago
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