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The number of ways in which a mixed double game can be arranged from amongst 9
married couples if no husband and wife play in the same game is?

6 years ago

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Answers : (2)

										

Dear  s adhithya


In mixed doubles, there are 2 men and 2 women..


2 men out of 9 can be selected in 9cways.


now we can only set 2 women out of 7.bec two the selected two men's wife can't play in a match


so in 7cwe can select women


now there are 2 men and 2 women M1, M2, W1,W2


possible combinatoin:


M1W1  and M2W2


M1W2 and M2W1..


so 2 possible combination..


hence answer= 9c*  7c*2


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Sahil Arora
6 years ago
										

Dear Sir,


I still have a doubt after seeing your reply. The answer you have given is what i arrived at myself on encountering the question in my bitsat sample paper, but on 2nd thoughts, i felt that besides the case of 2 men being chosen out of 9 and then 2 women being selected out of 7, there is also the possible case of 2 women being selected out of 9 and then  2 men being selected out of 7 and also the third case of 2 men being selected out of eight and then 2 women being selected out of 8 , i.e, a husband from 1 couple and a wife from another couple sit out. why aren't these 2 cases being considered?

6 years ago

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