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dear subham gupta
taking the probability of a failing as 15%
let
the probablity of a failing =p(a)=0.15
the probablity of b failing =p(b)=0.05
the probablity of c failing =p(c)=0.10
the probability that a wll fail in one year is (0.15*0.95*0.90)+(0.85*0.05*0.90)+(0.85*0.95*0.10)
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