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1^4/1.3+2^4/3.5+3^4/5.7+n^4/(2n+1)(2n-1)=n(4n^2+6n+5)/48+n/16(2n+1)

1^4/1.3+2^4/3.5+3^4/5.7+n^4/(2n+1)(2n-1)=n(4n^2+6n+5)/48+n/16(2n+1)

Grade:11

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
7 years ago
Hii

Whats the question in this.?? Kindly repost the question properly and we will get back at you

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