calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

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Vikas TU · Answer

Dear student Applyy the formula of mean free path , LAMBDA = 1/¶D2NV Where , D- density of molecule NV= NO. of Molecules Hope this clear good luck

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calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

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calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

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