A bomb of mass 1 kg is thrown vertically upwards with a speed of 100 m/s. After 5 seconds it explodes into 2 fragments. One fragment of mass 400 gm is found to go down with a speed of 25 m/s. What will happen to the second fragment just after the explosion? (g = 10m/s)

Question

Eshan · Answer

Dear student,

Velocity of the bomb after 5 seconds(at the time of explosion)= $u-gt=100-(10)(5)=50m/s$ upwards

Since no external force acts on the system in the explosion, the linear momentum of the system remains conserved.

Hence $m_{bomb}v_{bomb}=m_1v_1+m_2v_2$
$\implies (1)(+50)=(0.4)(-25)+(0.6)v_2$
$\implies v_2=+100m/s$
Hence the other fragment will move upwards with 100m/s.

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A bomb of mass 1 kg is thrown vertically upwards with a speed of 100 m/s. After 5 seconds it explodes into 2 fragments. One fragment of mass 400 gm is found to go down with a speed of 25 m/s. What will happen to the second fragment just after the explosion? (g = 10m/s)

A bomb of mass 1 kg is thrown vertically upwards with a speed of 100 m/s. After 5 seconds it explodes into 2 fragments. One fragment of mass 400 gm is found to go down with a speed of 25 m/s. What will happen to the second fragment just after the explosion? (g = 10m/s)

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A bomb of mass 1 kg is thrown vertically upwards with a speed of 100 m/s. After 5 seconds it explodes into 2 fragments. One fragment of mass 400 gm is found to go down with a speed of 25 m/s. What will happen to the second fragment just after the explosion? (g = 10m/s)

A bomb of mass 1 kg is thrown vertically upwards with a speed of 100 m/s. After 5 seconds it explodes into 2 fragments. One fragment of mass 400 gm is found to go down with a speed of 25 m/s. What will happen to the second fragment just after the explosion? (g = 10m/s)

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