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				   the value of lim x  tands to  infifnite of 

(e^x+x)^1/x is

6 years ago


Answers : (1)


Dear manan

y =Lt x→∞ (ex+x)1/x


lny = Lt x→∞ ln[(ex+x)]/x

      =Lt x→∞ ln[(ex+x)]/x

use L hospital rule

lny =Lt x→∞ (1+ex)/(ex+x)


lny = Lt x→∞ ex/(ex+1)


lny =Lt x→∞ 1/(e-x+1)

apply limit

lny =1

y =e

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6 years ago

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