Using factor theorem show that (a+b),(b+c) and (c+a) are factors of (a+b+c)^3 – {(a)^3 + (b)^3 +(c)^3}

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Vikas TU · Answer

If (a+b),(b+c) and (c+a) are the factors of of (a+b+c)^3 – {(a)^3 + (b)^3 +(c)^3} then, we can write of (a+b+c)^3 – {(a)^3 + (b)^3 +(c)^3} = (a+b) (b+c) (c+a) Take R.H.S and start multiplying them once each and then U would get Finally L.H.S

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Using factor theorem show that (a+b),(b+c) and (c+a) are factors of (a+b+c)^3 – {(a)^3 + (b)^3 +(c)^3}

Using factor theorem show that (a+b),(b+c) and (c+a) are factors of (a+b+c)^3 – {(a)^3 + (b)^3 +(c)^3}

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Using factor theorem show that (a+b),(b+c) and (c+a) are factors of (a+b+c)^3 – {(a)^3 + (b)^3 +(c)^3}

Using factor theorem show that (a+b),(b+c) and (c+a) are factors of (a+b+c)^3 – {(a)^3 + (b)^3 +(c)^3}

1 Answers

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