(a+b)^2 pol,mnhjknbvdrthbvcxsertybvcdftyujnbvcdfrtyujnbvcdftyjnbvfrtyujbvftyunbvftyujnbg

Question

vijay kale · Answer

This is a very popular algebraic identity (a+b )^2 =a^2+b^2+2ab. This can be easily proved with distributive proverty.

Om · Answer

Dear student Please check whether you wrote the correct question or not I hope you explain your question in an understanding way With regards Your Fellow tudent

Sayantan Garai · Answer

(a+b)&sup2;=a&sup2;+2ab+b&sup2;

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(a+b)^2 pol,mnhjknbvdrthbvcxsertybvcdftyujnbvcdfrtyujnbvcdftyjnbvfrtyujbvftyunbvftyujnbg

(a+b)^2 pol,mnhjknbvdrthbvcxsertybvcdftyujnbvcdfrtyujnbvcdftyjnbvfrtyujbvftyunbvftyujnbg

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(a+b)^2 pol,mnhjknbvdrthbvcxsertybvcdftyujnbvcdfrtyujnbvcdftyjnbvfrtyujbvftyunbvftyujnbg

(a+b)^2 pol,mnhjknbvdrthbvcxsertybvcdftyujnbvcdfrtyujnbvcdftyjnbvfrtyujbvftyunbvftyujnbg

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