If the difference between the roots of equation x^2+ax+1=0is less than √5,then the set of possible value of a is:

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Saswat Pani · Answer

x^2+ax+1=01ts root (-a + √a^2-4)/2 - (-a - √a^2-4)/2

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If the difference between the roots of equation x^2+ax+1=0is less than √5,then the set of possible value of a is:

If the difference between the roots of equation x^2+ax+1=0is less than √5,then the set of possible value of a is:

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If the difference between the roots of equation x^2+ax+1=0is less than √5,then the set of possible value of a is:

If the difference between the roots of equation x^2+ax+1=0is less than √5,then the set of possible value of a is:

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on 10 grade maths

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Answer and earn gift vouchers

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